Solution 2.1:1f
From Förberedande kurs i matematik 1
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The squaring rule <math> (a+b)^2 = a^2+2ab+b^2</math> with <math>a=5 </math> and <math> b=4y </math> gives | The squaring rule <math> (a+b)^2 = a^2+2ab+b^2</math> with <math>a=5 </math> and <math> b=4y </math> gives | ||
- | <math> | + | {{Displayed math||<math>\begin{align} |
- | &= 25+10\cdot 4y + 4^2y^2\\ | + | (5+4y)^2 &= 5^2+ 2\cdot 5 \cdot 4y +(4y)^2 \\[3pt] |
- | &= 25+40y+16y^ | + | &= 25+10\cdot 4y + 4^2y^2\\[3pt] |
- | &= 16y^2 +40y + 25 | + | &= 25+40y+16y^2\\[3pt] |
- | \end{align} | + | &= 16y^2 +40y + 25\,\textrm{.} |
- | </math> | + | \end{align}</math>}} |
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Current revision
The squaring rule \displaystyle (a+b)^2 = a^2+2ab+b^2 with \displaystyle a=5 and \displaystyle b=4y gives
\displaystyle \begin{align}
(5+4y)^2 &= 5^2+ 2\cdot 5 \cdot 4y +(4y)^2 \\[3pt] &= 25+10\cdot 4y + 4^2y^2\\[3pt] &= 25+40y+16y^2\\[3pt] &= 16y^2 +40y + 25\,\textrm{.} \end{align} |