Solution 1.1:2a
From Förberedande kurs i matematik 1
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- | + | The expression consists of two brackets | |
- | <center> [[ | + | <center><math>\bbox[#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}</math></center> |
- | + | which we can work out individually and then multiply together. | |
+ | In the expression in the first bracket, we calculate the inner bracket first | ||
+ | <center><math>(3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})</math></center> | ||
+ | and obtain that the expression in the first bracket becomes | ||
+ | <math>3-3=0</math>. | ||
+ | {{NAVCONTENT_STEP}} | ||
+ | The complete expression is 0 times <math>(6-5)</math>, and since 0 times anything is always 0 the answer is 0. | ||
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+ | <!--<center> [[Image:1_1_2a.gif]] </center> --> |
Current revision
The expression consists of two brackets
which we can work out individually and then multiply together. In the expression in the first bracket, we calculate the inner bracket first
and obtain that the expression in the first bracket becomes \displaystyle 3-3=0.
The complete expression is 0 times \displaystyle (6-5), and since 0 times anything is always 0 the answer is 0.