From Förberedande kurs i matematik 1

Revision as of 14:44, 31 March 2008 (edit) Lina (Talk | contribs) (Ny sida: {{NAVCONTENT_START}} <center> Bild:2_2_4b.gif </center> {{NAVCONTENT_STOP}}) ← Previous diff		Current revision (11:39, 24 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	By taking <math>4y</math> out of the relation <math>3x+4y-5=0</math>, we get
-	<center> [[Bild:2_2_4b.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>4y=-3x+5\,\textrm{.}</math>}}
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		+	Dividing by 4 then gives the answer in the desired form
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		+	{{Displayed math||<math>y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.}</math>}}

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Current revision

By taking \displaystyle 4y out of the relation \displaystyle 3x+4y-5=0, we get

\displaystyle 4y=-3x+5\,\textrm{.}

Dividing by 4 then gives the answer in the desired form

\displaystyle y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.}