From Förberedande kurs i matematik 1

Revision as of 14:26, 31 March 2008 (edit) Lina (Talk | contribs) (Ny sida: {{NAVCONTENT_START}} <center> Bild:2_2_1c.gif </center> {{NAVCONTENT_STOP}}) ← Previous diff		Current revision (13:19, 23 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	Because there is an ''x'' on both the left- and right-hand sides, the first step is to subtract ''x''/3 from both sides,
-	<center> [[Bild:2_2_1c.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>\tfrac{1}{3}x-1-\tfrac{1}{3}x=x-\tfrac{1}{3}x</math>}}
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		+	so as to collect ''x'' on the right-hand side
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		+	{{Displayed math||<math>-1=\tfrac{2}{3}x\,\textrm{.}</math>}}
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		+	Then, multiply both sides by 3/2,
		+
		+	{{Displayed math||<math>\tfrac{3}{2}\cdot (-1) = \tfrac{3}{2}\cdot\tfrac{2}{3}x\,,</math>}}
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		+	so that 2/3 can be eliminated on the right-hand side to give us
		+
		+	{{Displayed math||<math>-\tfrac{3}{2}=x\,\textrm{.}</math>}}

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Current revision

Because there is an x on both the left- and right-hand sides, the first step is to subtract x/3 from both sides,

\displaystyle \tfrac{1}{3}x-1-\tfrac{1}{3}x=x-\tfrac{1}{3}x

so as to collect x on the right-hand side

\displaystyle -1=\tfrac{2}{3}x\,\textrm{.}

Then, multiply both sides by 3/2,

\displaystyle \tfrac{3}{2}\cdot (-1) = \tfrac{3}{2}\cdot\tfrac{2}{3}x\,,

so that 2/3 can be eliminated on the right-hand side to give us

\displaystyle -\tfrac{3}{2}=x\,\textrm{.}