From Förberedande kurs i matematik 1

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-	{{NAVCONTENT_START}}	+	The expression can be rewritten as <math> x^2+2\cdot 3\cdot x+3^2 </math> and then we see that it can be factorized, using the squaring rule <math> x^2+2ax+a^2=(x+a)^2</math>, as
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-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math> x^2+6x+9 =x^2+2\cdot 3\cdot x+3^2=(x+3)^2\textrm{.}</math>}}

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The expression can be rewritten as \displaystyle x^2+2\cdot 3\cdot x+3^2 and then we see that it can be factorized, using the squaring rule \displaystyle x^2+2ax+a^2=(x+a)^2, as

\displaystyle x^2+6x+9 =x^2+2\cdot 3\cdot x+3^2=(x+3)^2\textrm{.}