From Förberedande kurs i matematik 1

Revision as of 09:51, 31 March 2008 (edit) Lina (Talk | contribs) (Ny sida: {{NAVCONTENT_START}} <center> Bild:2_1_3b.gif </center> {{NAVCONTENT_STOP}}) ← Previous diff		Current revision (08:30, 23 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	If we take out the factor 5, we see that the expression can be factorized using the conjugate rule
-	<center> [[Bild:2_1_3b.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>\begin{align}
		+	5x^2-20&=5(x^4-4)\\
		+	&= 5(x^2-2^2)\\
		+	&= 5(x+2)(x-2)\,\textrm{.}
		+	\end{align}</math>}}

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Current revision

If we take out the factor 5, we see that the expression can be factorized using the conjugate rule

\displaystyle \begin{align} 5x^2-20&=5(x^4-4)\\ &= 5(x^2-2^2)\\ &= 5(x+2)(x-2)\,\textrm{.} \end{align}