Solution 1.3:2a

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Current revision (12:53, 22 September 2008) (edit) (undo)
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We can write every factor in the expression as a power of
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We can write every factor in the expression as a power of 2,
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<math>2</math>,
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<math>\begin{align}
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& 2=2^{1} \\
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& \\
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& 4=2\centerdot 2=2^{2} \\
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& \\
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& 8=2\centerdot 4=2\centerdot 2\centerdot 2=2^{3} \\
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\end{align}</math>
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{{Displayed math||<math>\begin{align}
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2 &= 2^{1}\,, \\
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4 &= 2\cdot 2 = 2^{2}\,,\\
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8 &= 2\cdot 4 = 2\cdot 2\cdot 2 = 2^{3}\,,
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\end{align}</math>}}
which gives
which gives
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{{Displayed math||<math>2\cdot 4\cdot 8 = 2^{1}\cdot 2^{2}\cdot 2^{3} = 2^{1+2+3} = 2^{6}\,</math>.}}
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<math>2\centerdot 4\centerdot 8=2^{1}\centerdot 2^{2}\centerdot 2^{3}=2^{1+2+3}=2^{6}</math>
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Current revision

We can write every factor in the expression as a power of 2,

\displaystyle \begin{align}

2 &= 2^{1}\,, \\ 4 &= 2\cdot 2 = 2^{2}\,,\\ 8 &= 2\cdot 4 = 2\cdot 2\cdot 2 = 2^{3}\,, \end{align}

which gives

\displaystyle 2\cdot 4\cdot 8 = 2^{1}\cdot 2^{2}\cdot 2^{3} = 2^{1+2+3} = 2^{6}\,.
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