From Förberedande kurs i matematik 1

Revision as of 09:21, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 3.3:2c moved to Solution 3.3:2c: Robot: moved page) ← Previous diff		Current revision (14:30, 1 October 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	Because <math>\mathop{\text{lg}} 0\textrm{.}001</math> is defined as the exponent that should stand in the coloured box in the equality
-	<center> [[Image:3_3_2c.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}001</math>}}
		+
		+	and we have that
		+
		+	{{Displayed math||<math>10^{-3} = 0\textrm{.}001\,,</math>}}
		+
		+	thus <math>\mathop{\text{lg}} 0\textrm{.}0001 = -3\,</math>.

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Current revision

Because \displaystyle \mathop{\text{lg}} 0\textrm{.}001 is defined as the exponent that should stand in the coloured box in the equality

\displaystyle 10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}001

and we have that

\displaystyle 10^{-3} = 0\textrm{.}001\,,

thus \displaystyle \mathop{\text{lg}} 0\textrm{.}0001 = -3\,.