From Förberedande kurs i matematik 1

Revision as of 09:20, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 3.3:2a moved to Solution 3.3:2a: Robot: moved page) ← Previous diff		Current revision (14:25, 1 October 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	The logarithm <math>\mathop{\text{lg}} 0\textrm{.}1</math> is defined as that number which should stand in the coloured box in order that the equality
-	<center> [[Image:3_3_2a.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}1</math>}}
		+
		+	should hold. In this case, we see that
		+
		+	{{Displayed math||<math>10^{-1} = 0\textrm{.}1</math>}}
		+
		+	and therefore <math>\mathop{\text{lg}} 0\textrm{.}1 = -1\,</math>.

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Current revision

The logarithm \displaystyle \mathop{\text{lg}} 0\textrm{.}1 is defined as that number which should stand in the coloured box in order that the equality

\displaystyle 10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}1

should hold. In this case, we see that

\displaystyle 10^{-1} = 0\textrm{.}1

and therefore \displaystyle \mathop{\text{lg}} 0\textrm{.}1 = -1\,.