From Förberedande kurs i matematik 1

Revision as of 09:16, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 3.1:8c moved to Solution 3.1:8c: Robot: moved page) ← Previous diff		Current revision (14:29, 30 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	Since <math>2\textrm{.}5^{2} = 2\textrm{.}5\cdot 2\textrm{.}5 = 6\textrm{.}25\,</math>, then <math>2\textrm{.}5 = \sqrt{6\textrm{.}25}\,</math>, and then we see that <math>\sqrt{7}</math> is greater than 2.5 since <math>7^{1/2} > 6\textrm{.}25^{1/2}\,</math>.
-	<center> [[Image:3_1_8c.gif]] </center>	+
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Current revision

Since \displaystyle 2\textrm{.}5^{2} = 2\textrm{.}5\cdot 2\textrm{.}5 = 6\textrm{.}25\,, then \displaystyle 2\textrm{.}5 = \sqrt{6\textrm{.}25}\,, and then we see that \displaystyle \sqrt{7} is greater than 2.5 since \displaystyle 7^{1/2} > 6\textrm{.}25^{1/2}\,.