Solution 1.2:3a
From Förberedande kurs i matematik 1
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- | {{ | + | The denominator in the expression has 10 as a common factor, |
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- | {{ | + | {{Displayed math||<math>\frac{3}{2\cdot 10}+\frac{7}{5\cdot 10}-\frac{1}{10}\,</math>,}} |
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+ | and it is therefore sufficient to multiply the top and bottom of each fraction by the other factors in the denominators in order to obtain a common denominator, | ||
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+ | {{Displayed math||<math>\frac{3\cdot 5}{20\cdot 5}+\frac{7\cdot 2}{50\cdot 2}-\frac{1\cdot 5\cdot 2}{10\cdot 5\cdot 2}=\frac{15}{100}+\frac{14}{100}-\frac{10}{100}\,</math>.}} | ||
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+ | The lowest common denominator (LCD) is therefore 100, and the expression is equal to | ||
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+ | {{Displayed math||<math>\frac{15}{100}+\frac{14}{100}-\frac{10}{100}=\frac{15+14-10}{100}=\frac{19}{100}\,</math>.}} |
Current revision
The denominator in the expression has 10 as a common factor,
\displaystyle \frac{3}{2\cdot 10}+\frac{7}{5\cdot 10}-\frac{1}{10}\,, |
and it is therefore sufficient to multiply the top and bottom of each fraction by the other factors in the denominators in order to obtain a common denominator,
\displaystyle \frac{3\cdot 5}{20\cdot 5}+\frac{7\cdot 2}{50\cdot 2}-\frac{1\cdot 5\cdot 2}{10\cdot 5\cdot 2}=\frac{15}{100}+\frac{14}{100}-\frac{10}{100}\,. |
The lowest common denominator (LCD) is therefore 100, and the expression is equal to
\displaystyle \frac{15}{100}+\frac{14}{100}-\frac{10}{100}=\frac{15+14-10}{100}=\frac{19}{100}\,. |