Solution 1.3:6b

From Förberedande kurs i matematik 1

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Current revision (14:48, 22 September 2008) (edit) (undo)
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When a power expression has a negative exponent, the expression's value decreases when the base increases. Thus
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<center> [[Image:1_3_6b.gif]] </center>
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{{Displayed math||<math>0\textrm{.}4^{-3} > 0\textrm{.}5^{-3}</math>.}}
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Another way to see this is to rewrite the two powers as
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{{Displayed math||<math>0\textrm{.}5^{-3}=\frac{1}{0\textrm{.}5^{3}}\quad</math> and <math>\quad 0\textrm{.}4^{-3}=\frac{1}{0\textrm{.}4^3}</math>}}
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and because <math>0\textrm{.}5^{3} > 0\textrm{.}4^{3}</math> (see exercise a), it follows that
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{{Displayed math||<math>\frac{1}{0\textrm{.}4^{3}} > \frac{1}{0\textrm{.}5^{3}}\,</math>,}}
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i.e. <math>0\textrm{.}4^{-3} > 0\textrm{.}5^{-3}\,</math>.

Current revision

When a power expression has a negative exponent, the expression's value decreases when the base increases. Thus

\displaystyle 0\textrm{.}4^{-3} > 0\textrm{.}5^{-3}.

Another way to see this is to rewrite the two powers as

\displaystyle 0\textrm{.}5^{-3}=\frac{1}{0\textrm{.}5^{3}}\quad and \displaystyle \quad 0\textrm{.}4^{-3}=\frac{1}{0\textrm{.}4^3}

and because \displaystyle 0\textrm{.}5^{3} > 0\textrm{.}4^{3} (see exercise a), it follows that

\displaystyle \frac{1}{0\textrm{.}4^{3}} > \frac{1}{0\textrm{.}5^{3}}\,,

i.e. \displaystyle 0\textrm{.}4^{-3} > 0\textrm{.}5^{-3}\,.