Solution 1.3:1a
From Förberedande kurs i matematik 1
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| - | {{ | + | We calculate <math>2^{3}</math> first and then <math>3^{2}</math>, |
| - | < | + | |
| - | {{ | + | {{Displayed math||<math>\begin{align} |
| + | 2^{3} &= 2\cdot 2\cdot 2 = 4\cdot 2 = 8\,,\\[5pt] | ||
| + | 3^{2} &= 3\cdot 3=9\,\textrm{.} | ||
| + | \end{align}</math>}} | ||
| + | |||
| + | Hence, | ||
| + | |||
| + | {{Displayed math||<math>2^{3}\cdot 3^{2}=8\cdot 9=72\,</math>.}} | ||
Current revision
We calculate \displaystyle 2^{3} first and then \displaystyle 3^{2},
| \displaystyle \begin{align}
2^{3} &= 2\cdot 2\cdot 2 = 4\cdot 2 = 8\,,\\[5pt] 3^{2} &= 3\cdot 3=9\,\textrm{.} \end{align} |
Hence,
| \displaystyle 2^{3}\cdot 3^{2}=8\cdot 9=72\,. |
