3.4 Exercises

From Förberedande kurs i matematik 1

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</div>{{#NAVCONTENT:Answer|Answer 3.4:1|Solution a|Lösning 3.4:1a|Solution b|Lösning 3.4:1b|Solution c|Lösning 3.4:1c}}
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</div>{{#NAVCONTENT:Answer|Answer 3.4:1|Solution a|Solution 3.4:1a|Solution b|Solution 3.4:1b|Solution c|Solution 3.4:1c}}
===Exercise 3.4:2===
===Exercise 3.4:2===
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===Exercise 3.4:3===
===Exercise 3.4:3===
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Current revision

       Theory          Exercises      


Exercise 3.4:1

Solve the equation

a) \displaystyle e^x=13 b) \displaystyle 13e^x=2\cdot3^{-x} c) \displaystyle 3e^x=7\cdot2^x
Answer
Answer 3.4:1
Solution a
Solution 3.4:1a
Solution b
Solution 3.4:1b
Solution c
Solution 3.4:1c

Exercise 3.4:2

Solve the equation

a) \displaystyle 2^{\scriptstyle x^2-2}=1 b) \displaystyle e^{2x}+e^x=4 c) \displaystyle 3e^{x^2}=2^x
Answer
Answer 3.4:2
Solution a
Solution 3.4:2a
Solution b
Solution 3.4:2b
Solution c
Solution 3.4:2c

Exercise 3.4:3

Solve the equation

a) \displaystyle 2^{-x^2}=2e^{2x} b) \displaystyle \ln{(x^2+3x)}=\ln{(3x^2-2x)}
c) \displaystyle \ln{x}+\ln{(x+4)}=\ln{(2x+3)}
Answer
Answer 3.4:3
Solution a
Solution 3.4:3a
Solution b
Solution 3.4:3b
Solution c
Solution 3.4:3c
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