Solution 4.2:1f
From Förberedande kurs i matematik 1
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- | + | The side adjacent to the angle of 50° is marked ''x'' and the opposite is the side of length 19. | |
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- | {{ | + | [[Image:4_2_1_f.gif|center]] |
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+ | If we write the tangent for the angle, this gives a relation which contains ''x'' as the only unknown, | ||
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+ | {{Displayed math||<math>\tan 50^{\circ} = \frac{19}{x}\,\textrm{.}</math>}} | ||
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+ | This gives | ||
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+ | {{Displayed math||<math>x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}</math>}} |
Current revision
The side adjacent to the angle of 50° is marked x and the opposite is the side of length 19.
If we write the tangent for the angle, this gives a relation which contains x as the only unknown,
\displaystyle \tan 50^{\circ} = \frac{19}{x}\,\textrm{.} |
This gives
\displaystyle x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.} |