Solution 4.1:6b

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A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (''a'',''b'') and radius ''r'',
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[[Bild:4_1_6_b.gif]]
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<center> [[Bild:4_1_6b.gif]] </center>
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{{Displayed math||<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}
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In our case, we can write the equation as
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{{Displayed math||<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}
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and then we see that it describes a circle with centre at (1,2) and radius <math>\sqrt{3}\,</math>.
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[[Image:4_1_6_b.gif|center]]

Current revision

A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (a,b) and radius r,

\displaystyle (x-a)^2 + (y-b)^2 = r^2\,\textrm{.}

In our case, we can write the equation as

\displaystyle (x-1)^2 + (y-2)^2 = (\sqrt{3})^2

and then we see that it describes a circle with centre at (1,2) and radius \displaystyle \sqrt{3}\,.


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