Solution 1.1:7c

From Förberedande kurs i matematik 1

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Current revision (07:18, 19 September 2008) (edit) (undo)
m (decimal comma --> decimal point)
 
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If we look more closely at this number, we see that the combination 001 is repeated from the second decimal place onwards,
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<center><math>0\textrm{.}2\ \underline{001}\ \underline{001}\ \underline{001}\,\ldots</math></center>
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and this reveals that the number is rational.
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By multiplying a certain number of times by 10 we can move the decimal place step by step to the right
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::<math>\insteadof[right]{10000x}{x}{}=0\,\textrm{.}\,2\ 001\ 001\ 001\,\ldots</math>
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::<math>\insteadof[right]{10000x}{10x}{}=2\,\textrm{.}\,\underline{001}\ \underline{001}\ \underline{001}\ 1\ldots</math>
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::<math>\insteadof[right]{10000x}{100x}{}=20\,\textrm{.}\,01\ 001\ 001\ 1\ldots</math>
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::<math>\insteadof[right]{10000x}{1000x}{}=200\,\textrm{.}\,1\ 001\ 001\ 1\ldots</math>
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::<math>\insteadof[right]{10000x}{10000x}{}=2001\,\textrm{.}\,\underline{001}\ \underline{001}\ 1\ldots</math>
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In this list, we see that 10''x'' and 10000''x'' have the same decimal expansion, which means that
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::<math>10000x-10x = 2001\textrm{.}\underline{001}\ \underline{001}\ \underline{001}\,\ldots - 2\textrm{.}\underline{001}\ \underline{001}\ \underline{001}\,\ldots</math>
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::<math>\phantom{10000x-10x}{} = 1999\,\mbox{.}\quad</math>(decimal parts cancel)
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As <math>10000x-10x = 9990x</math> then
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::<math>9990x = 1999\quad\Leftrightarrow\quad x = \frac{1999}{9990}\,\mbox{.}</math>
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