Solution 1.1:4c
From Förberedande kurs i matematik 1
(Difference between revisions)
(Ny sida: {{NAVCONTENT_START}} <center> Bild:1_1_4c.gif </center> {{NAVCONTENT_STOP}}) |
|||
(3 intermediate revisions not shown.) | |||
Line 1: | Line 1: | ||
- | {{ | + | <math>\sqrt{2}</math> is not a rational number, i.e. it cannot be written as a ratio of two integers, and neither |
- | <center> [[ | + | is it possible to write |
- | + | <math>\sqrt{2}/3</math> as a ratio of two integers. The number | |
+ | <math>\sqrt{2}/3</math> is thus irrational. | ||
+ | |||
+ | <!--<center> [[Image:1_1_4c.gif]] </center>--> |
Current revision
\displaystyle \sqrt{2} is not a rational number, i.e. it cannot be written as a ratio of two integers, and neither is it possible to write \displaystyle \sqrt{2}/3 as a ratio of two integers. The number \displaystyle \sqrt{2}/3 is thus irrational.