Solution 4.2:2a

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
m (Lösning 4.2:2a moved to Solution 4.2:2a: Robot: moved page)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
The opposite and adjacent are given in the right-angled triangle and this means that the value of the tangent for the angle can be determined as the quotient between the opposite and the adjacent:
-
<center> [[Image:4_2_2a.gif]] </center>
+
 
-
{{NAVCONTENT_STOP}}
+
 
 +
<math>\text{tan }v\text{ }={2}/{5}\;~</math>
 +
 
 +
 
[[Image:4_2_2_a.gif|center]]
[[Image:4_2_2_a.gif|center]]
 +
 +
At the same time, this is a trigonometric equation for the angle
 +
<math>v</math>.
 +
 +
NOTE: In the chapter on "Trigonometric equations", we will investigate more closely how to solve equations of this type.

Revision as of 09:09, 10 October 2008

The opposite and adjacent are given in the right-angled triangle and this means that the value of the tangent for the angle can be determined as the quotient between the opposite and the adjacent:


\displaystyle \text{tan }v\text{ }={2}/{5}\;~


At the same time, this is a trigonometric equation for the angle \displaystyle v.

NOTE: In the chapter on "Trigonometric equations", we will investigate more closely how to solve equations of this type.

Retrieved from "http://wiki.sommarmatte.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_4.2:2a"