Solution 4.2:5c

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Current revision (11:11, 9 October 2008) (edit) (undo)
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If we express the angle
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If we express the angle 330° in radians, we obtain
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<math>\text{33}0^{\circ }</math>
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in radians, we obtain
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{{Displayed math||<math>330^{\circ} = 330^{\circ}\cdot \frac{\pi}{180^{\circ}}\ \text{radians} = \frac{11\pi}{6}\ \text{radians}</math>}}
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<math>\text{33}0^{\circ }=\text{33}0^{\circ }\centerdot \frac{\pi }{180^{\circ }}</math>
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and from exercise 3.3:1g, we know that
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radians
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<math>=\frac{11\pi }{6}</math>
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radians
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and from exercise 3.3:1g, we know that
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{{Displayed math||<math>\cos 330^{\circ} = \cos \frac{11\pi}{6} = \frac{\sqrt{3}}{2}\,\textrm{.}</math>}}
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<math>\cos 330^{\circ }=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}</math>.
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Current revision

If we express the angle 330° in radians, we obtain

\displaystyle 330^{\circ} = 330^{\circ}\cdot \frac{\pi}{180^{\circ}}\ \text{radians} = \frac{11\pi}{6}\ \text{radians}

and from exercise 3.3:1g, we know that

\displaystyle \cos 330^{\circ} = \cos \frac{11\pi}{6} = \frac{\sqrt{3}}{2}\,\textrm{.}
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