Solution 4.2:3a

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Current revision (07:45, 9 October 2008) (edit) (undo)
m
 
(4 intermediate revisions not shown.)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
A useful technique for calculating the value of a trigonometric function for angles that don't lie between <math>0</math> and <math>{\pi }/{2}\;</math> is to use the unit circle. If we draw a line which starts at the origin and makes a certain angle relative to the positive part of the ''x''-axis, we can see that the cosine of that angle is the ''x''-coordinate of the point of intersection between the line and the unit circle. In the same way, the sine of the angle is the ''y''-coordinate of the intersection point.
-
<center> [[Bild:4_2_3a.gif]] </center>
+
 
-
{{NAVCONTENT_STOP}}
+
[[Image:4_2_3_a1.gif|center]]
-
[[Bild:4_2_3_a1.gif|center]]
+
 
 +
In this case, we see immediately that <math>\sin\Bigl(-\frac{\pi}{2}\Bigr) = -1\,</math>.
 +
 
 +
[[Image:4_2_3_a2.gif|center]]

Current revision

A useful technique for calculating the value of a trigonometric function for angles that don't lie between \displaystyle 0 and \displaystyle {\pi }/{2}\; is to use the unit circle. If we draw a line which starts at the origin and makes a certain angle relative to the positive part of the x-axis, we can see that the cosine of that angle is the x-coordinate of the point of intersection between the line and the unit circle. In the same way, the sine of the angle is the y-coordinate of the intersection point.

In this case, we see immediately that \displaystyle \sin\Bigl(-\frac{\pi}{2}\Bigr) = -1\,.