Solution 4.2:1f

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
(Ny sida: {{NAVCONTENT_START}} <center> Bild:4_2_1f.gif </center> {{NAVCONTENT_STOP}})
Current revision (14:22, 8 October 2008) (edit) (undo)
m
 
(4 intermediate revisions not shown.)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
The side adjacent to the angle of 50° is marked ''x'' and the opposite is the side of length 19.
-
<center> [[Bild:4_2_1f.gif]] </center>
+
 
-
{{NAVCONTENT_STOP}}
+
[[Image:4_2_1_f.gif|center]]
 +
 
 +
If we write the tangent for the angle, this gives a relation which contains ''x'' as the only unknown,
 +
 
 +
{{Displayed math||<math>\tan 50^{\circ} = \frac{19}{x}\,\textrm{.}</math>}}
 +
 
 +
This gives
 +
 
 +
{{Displayed math||<math>x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}</math>}}

Current revision

The side adjacent to the angle of 50° is marked x and the opposite is the side of length 19.

If we write the tangent for the angle, this gives a relation which contains x as the only unknown,

\displaystyle \tan 50^{\circ} = \frac{19}{x}\,\textrm{.}

This gives

\displaystyle x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}