From Förberedande kurs i matematik 1

Revision as of 09:40, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 4.2:1d moved to Solution 4.2:1d: Robot: moved page) ← Previous diff		Current revision (14:10, 8 October 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	The side marked ''x'' is the hypotenuse in the right-angled triangle and the side of length 16 is the adjacent to the angle of 20°.
-	<center> [[Image:4_2_1d.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+
	[[Image:4_2_1_d.gif|center]]		[[Image:4_2_1_d.gif|center]]
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		+	By writing the quotient for <math>\cos 20^{\circ}</math>, we obtain the relation
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		+	{{Displayed math||<math>\cos 20^{\circ} = \frac{16}{x}</math>}}
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		+	and this gives
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		+	{{Displayed math||<math>x = \frac{16}{\cos20^{\circ}}\quad ({}\approx 17\textrm{.}0)\,\textrm{.}</math>}}

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Current revision

The side marked x is the hypotenuse in the right-angled triangle and the side of length 16 is the adjacent to the angle of 20°.

By writing the quotient for \displaystyle \cos 20^{\circ}, we obtain the relation

\displaystyle \cos 20^{\circ} = \frac{16}{x}

and this gives

\displaystyle x = \frac{16}{\cos20^{\circ}}\quad ({}\approx 17\textrm{.}0)\,\textrm{.}