Solution 4.2:1a

From Förberedande kurs i matematik 1

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{{NAVCONTENT_START}}
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The definition of the tangent states that
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<center> [[Image:4_2_1a.gif]] </center>
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{{NAVCONTENT_STOP}}
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{| width="100%"
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[[Image:4_2_1_a.gif|center]]
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| width="50%" align="center"|<math>\tan u=\frac{\text{opposite}}{\text{adjacent}}</math>
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| width="50%" align="center"|[[Image:4_2_1_a.gif]]
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|}
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In our case, this means that
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{{Displayed math||<math>\tan 27^{\circ} = \frac{x}{13}</math>}}
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which gives <math>x = 13\cdot \tan 27^{\circ}\,</math>.
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Note: Using a calculator, we can work out what ''x'' should be,
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{{Displayed math||<math>x = 13\cdot\tan 27^{\circ} \approx 6\textrm{.}62\,\textrm{.}</math>}}

Current revision

The definition of the tangent states that

\displaystyle \tan u=\frac{\text{opposite}}{\text{adjacent}} Image:4_2_1_a.gif

In our case, this means that

\displaystyle \tan 27^{\circ} = \frac{x}{13}

which gives \displaystyle x = 13\cdot \tan 27^{\circ}\,.


Note: Using a calculator, we can work out what x should be,

\displaystyle x = 13\cdot\tan 27^{\circ} \approx 6\textrm{.}62\,\textrm{.}