From Förberedande kurs i matematik 1

Revision as of 09:36, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 4.1:5a moved to Solution 4.1:5a: Robot: moved page) ← Previous diff		Current revision (10:47, 7 October 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	A circle is defined as all the points which have a fixed distance to the circle's midpoint. Hence, a point (''x'',''y'') lies on our circle if and only if its distance to the point (1,3) is exactly 2. Using the distance formula, we can express this condition as
-	[[Image:4_1_5_a.gif|center]]	+
-	<center> [[Image:4_1_5a.gif]] </center>	+	{{Displayed math||<math>\sqrt{(x-1)^2 + (y-2)^2} = 2\,\textrm{.}</math>}}
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		+	After squaring, we obtain the equation of the circle in standard form,
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		+	{{Displayed math||<math>(x-1)^2 + (y-2)^2 = 4\,\textrm{.}</math>}}
		+
		+
		+	[[Image:4_1_5_a.gif|center]]

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Current revision

A circle is defined as all the points which have a fixed distance to the circle's midpoint. Hence, a point (x,y) lies on our circle if and only if its distance to the point (1,3) is exactly 2. Using the distance formula, we can express this condition as

\displaystyle \sqrt{(x-1)^2 + (y-2)^2} = 2\,\textrm{.}

After squaring, we obtain the equation of the circle in standard form,

\displaystyle (x-1)^2 + (y-2)^2 = 4\,\textrm{.}