Solution 4.1:4b

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Current revision (10:30, 7 October 2008) (edit) (undo)
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If we use the distance formula
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<center> [[Bild:4_1_4b.gif]] </center>
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{{Displayed math||<math>d=\sqrt{(x-a)^2+(y-b)^2}</math>}}
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to determine the distance between the points <math>(x,y) = (-2,5)</math> and <math>(a,b) = (3,-1)</math>, we get
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{{Displayed math||<math>\begin{align}
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d &= \sqrt{(-2-3)^2+(5-(-1))^2}\\[5pt]
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&= \sqrt{(-5)^2+6^2}\\[5pt]
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&= \sqrt{25+36}\\[5pt]
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&= \sqrt{61}\,\textrm{.}
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\end{align}</math>}}

Current revision

If we use the distance formula

\displaystyle d=\sqrt{(x-a)^2+(y-b)^2}

to determine the distance between the points \displaystyle (x,y) = (-2,5) and \displaystyle (a,b) = (3,-1), we get

\displaystyle \begin{align}

d &= \sqrt{(-2-3)^2+(5-(-1))^2}\\[5pt] &= \sqrt{(-5)^2+6^2}\\[5pt] &= \sqrt{25+36}\\[5pt] &= \sqrt{61}\,\textrm{.} \end{align}