Solution 3.3:5f
From Förberedande kurs i matematik 1
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| - | + | Since <math>\ln e=1</math>, the whole expression becomes | |
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| - | {{ | + | {{Displayed math||<math>\bigl(e^{\ln e}\bigr)^2 = \bigl(e^{1}\bigr)^2 = e^{1\cdot 2} = e^2\,\textrm{.}</math>}} |
Current revision
Since \displaystyle \ln e=1, the whole expression becomes
| \displaystyle \bigl(e^{\ln e}\bigr)^2 = \bigl(e^{1}\bigr)^2 = e^{1\cdot 2} = e^2\,\textrm{.} |
