Solution 3.3:2c
From Förberedande kurs i matematik 1
(Difference between revisions)
m (Robot: Automated text replacement (-[[Bild: +[[Image:)) |
m |
||
| (2 intermediate revisions not shown.) | |||
| Line 1: | Line 1: | ||
| - | {{ | + | Because <math>\mathop{\text{lg}} 0\textrm{.}001</math> is defined as the exponent that should stand in the coloured box in the equality |
| - | < | + | |
| - | {{ | + | {{Displayed math||<math>10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}001</math>}} |
| + | |||
| + | and we have that | ||
| + | |||
| + | {{Displayed math||<math>10^{-3} = 0\textrm{.}001\,,</math>}} | ||
| + | |||
| + | thus <math>\mathop{\text{lg}} 0\textrm{.}0001 = -3\,</math>. | ||
Current revision
Because \displaystyle \mathop{\text{lg}} 0\textrm{.}001 is defined as the exponent that should stand in the coloured box in the equality
| \displaystyle 10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}001 |
and we have that
| \displaystyle 10^{-3} = 0\textrm{.}001\,, |
thus \displaystyle \mathop{\text{lg}} 0\textrm{.}0001 = -3\,.
