From Förberedande kurs i matematik 1

Revision as of 08:15, 18 September 2008 (edit) Ian (Talk | contribs) ← Previous diff		Current revision (11:39, 24 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	By taking	+	By taking <math>4y</math> out of the relation <math>3x+4y-5=0</math>, we get
-	<math>4y</math>	+
-	out of the relation	+
-	<math>3x+4y-5=0</math>, we get	+
		+	{{Displayed math||<math>4y=-3x+5\,\textrm{.}</math>}}
-	<math>4y=-3x+5</math>	+	Dividing by 4 then gives the answer in the desired form
-		+	{{Displayed math||<math>y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.}</math>}}
-	Dividing by	+
-	<math>4</math>	+
-	then gives the answer in the desired form:	+
-		+
-		+
-	<math>y=-\frac{3}{4}x+\frac{5}{4}</math>	+

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Current revision

By taking \displaystyle 4y out of the relation \displaystyle 3x+4y-5=0, we get

\displaystyle 4y=-3x+5\,\textrm{.}

Dividing by 4 then gives the answer in the desired form

\displaystyle y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.}