From Förberedande kurs i matematik 1

Revision as of 14:26, 31 March 2008 (edit) Lina (Talk | contribs) (Ny sida: {{NAVCONTENT_START}} <center> Bild:2_2_1d.gif </center> {{NAVCONTENT_STOP}}) ← Previous diff		Current revision (13:23, 23 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	Move ''x'' to the left-hand side by subtracting 2''x'' from both sides,
-	<center> [[Bild:2_2_1d.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>5x+7-2x=2x-6-2x</math>}}
		+
		+	which gives
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		+	{{Displayed math||<math>3x+7=-6\,\textrm{.}</math>}}
		+
		+	Subtract 7 from both sides,
		+
		+	{{Displayed math||<math>3x+7-7=-6-7</math>}}
		+
		+	so that the term 3''x'' alone remains on the left-hand side
		+
		+	{{Displayed math||<math>3x=-13\,\textrm{.}</math>}}
		+
		+	Then, divide both sides by 3,
		+
		+	{{Displayed math||<math>\frac{3x}{3}=-\frac{13}{3}\,\textrm{,}</math>}}
		+
		+	to get x,
		+
		+	{{Displayed math||<math>x=-\frac{13}{3}\,\textrm{.}</math>}}

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Current revision

Move x to the left-hand side by subtracting 2x from both sides,

\displaystyle 5x+7-2x=2x-6-2x

which gives

\displaystyle 3x+7=-6\,\textrm{.}

Subtract 7 from both sides,

\displaystyle 3x+7-7=-6-7

so that the term 3x alone remains on the left-hand side

\displaystyle 3x=-13\,\textrm{.}

Then, divide both sides by 3,

\displaystyle \frac{3x}{3}=-\frac{13}{3}\,\textrm{,}

to get x,

\displaystyle x=-\frac{13}{3}\,\textrm{.}