Solution 1.3:5c
From Förberedande kurs i matematik 1
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- | { | + | We can write <math>9 = 3\cdot 3 = 3^{2}</math> and then the power rules give |
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- | {{ | + | {{Displayed math||<math>9^{\frac{3}{2}} = \bigl(3^{2}\bigr)^{\frac{3}{2}} = 3^{2\cdot \frac{3}{2}} = 3^{3} = 3\cdot 3\cdot 3 = 27\,</math>.}} |
Current revision
We can write \displaystyle 9 = 3\cdot 3 = 3^{2} and then the power rules give
\displaystyle 9^{\frac{3}{2}} = \bigl(3^{2}\bigr)^{\frac{3}{2}} = 3^{2\cdot \frac{3}{2}} = 3^{3} = 3\cdot 3\cdot 3 = 27\,. |