Solution 1.2:1c

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Current revision (07:34, 19 September 2008) (edit) (undo)
m
 
Line 1: Line 1:
We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
 +
{{Displayed math||<math>\frac{1}{6}-\frac{2}{5}=\frac{1\cdot 5}{6\cdot 5}-\frac{2\cdot 6}{5\cdot 6}=\frac{5}{30}-\frac{12}{30}\,</math>.}}
-
<math>\frac{1}{6}-\frac{2}{5}=\frac{1\centerdot 5}{6\centerdot 5}-\frac{2\centerdot 6}{5\centerdot 6}=\frac{5}{30}-\frac{12}{30}</math>
+
Then the numerators can be subtracted
-
 
+
{{Displayed math||<math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}\,</math>.}}
-
Then the numerators can be subtracted:
+
-
 
+
-
 
+
-
<math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}</math>
+

Current revision

We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,

\displaystyle \frac{1}{6}-\frac{2}{5}=\frac{1\cdot 5}{6\cdot 5}-\frac{2\cdot 6}{5\cdot 6}=\frac{5}{30}-\frac{12}{30}\,.

Then the numerators can be subtracted

\displaystyle \frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}\,.
Retrieved from "http://wiki.sommarmatte.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_1.2:1c"