From Förberedande kurs i matematik 1

Revision as of 08:48, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 2.2:5e moved to Solution 2.2:5e: Robot: moved page) ← Previous diff		Revision as of 10:05, 18 September 2008 (edit) (undo) Ian (Talk | contribs) Next diff →
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		+	The line should go through the points
		+	<math>\left( 5 \right.,\left. 0 \right)</math>
		+	and
		+	<math>\left( 0 \right.,\left. -8 \right)</math>
		+	which must therefore satisfy the equation of the line
		+	<math>y=kx+m</math>, i.e.
		+
		+
		+	<math>0=k\centerdot 5+m</math>
		+
		+
		+	From the other equation, we get
		+	<math>m=-8</math>
		+	and substituting this into the first equation gives
		+
		+
		+	<math>0=5k-8\ \Leftrightarrow \ k={8}/{5}\;</math>
		+
		+
		+	The gradient of the line is
		+	<math>{8}/{5}\;</math>.
		+
		+
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Revision as of 10:05, 18 September 2008

The line should go through the points \displaystyle \left( 5 \right.,\left. 0 \right) and \displaystyle \left( 0 \right.,\left. -8 \right) which must therefore satisfy the equation of the line \displaystyle y=kx+m, i.e.

\displaystyle 0=k\centerdot 5+m

From the other equation, we get \displaystyle m=-8 and substituting this into the first equation gives

\displaystyle 0=5k-8\ \Leftrightarrow \ k={8}/{5}\;

The gradient of the line is \displaystyle {8}/{5}\;.