Solution 1.3:5b
From Förberedande kurs i matematik 1
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- | + | If we use | |
- | < | + | <math>4=2\centerdot 2=2^{2}</math>, the power rules give |
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+ | <math>4^{-\frac{1}{2}}=\left( 2^{2} \right)^{-\frac{1}{2}}=2^{2\centerdot \left( -\frac{1}{2} \right)}=2^{-1}=\frac{1}{2}</math> |
Revision as of 12:01, 15 September 2008
If we use \displaystyle 4=2\centerdot 2=2^{2}, the power rules give
\displaystyle 4^{-\frac{1}{2}}=\left( 2^{2} \right)^{-\frac{1}{2}}=2^{2\centerdot \left( -\frac{1}{2} \right)}=2^{-1}=\frac{1}{2}