Solution 1.1:4c

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
(Ny sida: {{NAVCONTENT_START}} <center> Bild:1_1_4c.gif </center> {{NAVCONTENT_STOP}})
Current revision (13:54, 13 September 2008) (edit) (undo)
 
(3 intermediate revisions not shown.)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
<math>\sqrt{2}</math> is not a rational number, i.e. it cannot be written as a ratio of two integers, and neither
-
<center> [[Bild:1_1_4c.gif]] </center>
+
is it possible to write
-
{{NAVCONTENT_STOP}}
+
<math>\sqrt{2}/3</math> as a ratio of two integers. The number
 +
<math>\sqrt{2}/3</math> is thus irrational.
 +
 
 +
<!--<center> [[Image:1_1_4c.gif]] </center>-->

Current revision

\displaystyle \sqrt{2} is not a rational number, i.e. it cannot be written as a ratio of two integers, and neither is it possible to write \displaystyle \sqrt{2}/3 as a ratio of two integers. The number \displaystyle \sqrt{2}/3 is thus irrational.


Retrieved from "http://wiki.sommarmatte.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_1.1:4c"