Solution 1.2:1c
From Förberedande kurs i matematik 1
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- | {{ | + | We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator, |
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+ | <math>\frac{1}{6}-\frac{2}{5}=\frac{1\centerdot 5}{6\centerdot 5}-\frac{2\centerdot 6}{5\centerdot 6}=\frac{5}{30}-\frac{12}{30}</math> | ||
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+ | Then the numerators can be subtracted: | ||
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+ | <math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}</math> |
Revision as of 11:37, 11 September 2008
We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
\displaystyle \frac{1}{6}-\frac{2}{5}=\frac{1\centerdot 5}{6\centerdot 5}-\frac{2\centerdot 6}{5\centerdot 6}=\frac{5}{30}-\frac{12}{30}
Then the numerators can be subtracted:
\displaystyle \frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}