Answer 3.4:1
From Förberedande kurs i matematik 1
(Difference between revisions)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math>x=\ln 13</math> |b) |width="33%" | <math>x=\displaystyle\frac{\ln 2 - \ln 13}{1+\ln 3}</math> |c) |width="33%" | <math>x=\displa...) |
m (Svar 3.4:1 moved to Answer 3.4:1: Robot: moved page) |
Current revision
| a) | \displaystyle x=\ln 13 | b) | \displaystyle x=\displaystyle\frac{\ln 2 - \ln 13}{1+\ln 3} | c) | \displaystyle x=\displaystyle\frac{\ln 7 - \ln 3}{1-\ln 2} |
