Answer 2.1:3

From Förberedande kurs i matematik 1

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <(x+6)(x-6)</math> |b) |width="33%" | <math>5(x+2)(x-2)</math> |c) |width="33%" | <math>$(x+3)^2</math> |- |d) || <math>(x-5)^2</math>...)
Current revision (14:32, 8 September 2008) (edit) (undo)
m (Svar 2.1:3 moved to Answer 2.1:3: Robot: moved page)
 
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{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="33%" | <(x+6)(x-6)</math>
+
|width="33%" | <math>(x+6)(x-6)</math>
|b)
|b)
|width="33%" | <math>5(x+2)(x-2)</math>
|width="33%" | <math>5(x+2)(x-2)</math>
|c)
|c)
-
|width="33%" | <math>$(x+3)^2</math>
+
|width="33%" | <math>(x+3)^2</math>
|-
|-
|d)
|d)

Current revision

a) \displaystyle (x+6)(x-6) b) \displaystyle 5(x+2)(x-2) c) \displaystyle (x+3)^2
d) \displaystyle (x-5)^2 e) \displaystyle -2x(x+3)(x-3) f) \displaystyle (4x+1)^2