Solution 2.1:3f
From Förberedande kurs i matematik 1
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<math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math> | <math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math> | ||
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Revision as of 06:35, 21 August 2008
Treating \displaystyle 4x as one term, we can write
\displaystyle \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1
and since \displaystyle y^2 +2y+1=(y+1)^2 we obtain
\displaystyle \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2
