1.2 Exercises
From Förberedande kurs i matematik 1
(Difference between revisions)
m (Regerate images and tabs) |
|||
| Line 10: | Line 10: | ||
===Övning 1.2:1=== | ===Övning 1.2:1=== | ||
<div class="ovning"> | <div class="ovning"> | ||
| - | + | Write as one fraction | |
{| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
|a) | |a) | ||
| Line 29: | Line 29: | ||
===Övning 1.2:2=== | ===Övning 1.2:2=== | ||
<div class="ovning"> | <div class="ovning"> | ||
| - | + | Determine the lowest common denominator of | |
{| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
|a) | |a) | ||
| Line 46: | Line 46: | ||
===Övning 1.2:3=== | ===Övning 1.2:3=== | ||
<div class="ovning"> | <div class="ovning"> | ||
| - | + | Calcualte the following by using the lowest common denominator. | |
{| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
|a) | |a) | ||
| Line 58: | Line 58: | ||
===Övning 1.2:4=== | ===Övning 1.2:4=== | ||
<div class="ovning"> | <div class="ovning"> | ||
| - | + | Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form. | |
{| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
|a) | |a) | ||
| Line 72: | Line 72: | ||
===Övning 1.2:5=== | ===Övning 1.2:5=== | ||
<div class="ovning"> | <div class="ovning"> | ||
| - | + | Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form. | |
{| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
|a) | |a) | ||
| Line 86: | Line 86: | ||
===Övning 1.2:6=== | ===Övning 1.2:6=== | ||
<div class="ovning"> | <div class="ovning"> | ||
| - | + | Simplify | |
| + | <math>\ \,\displaystyle \frac{\displaystyle \frac{2}{\displaystyle 3+\frac{1}{2}}\displaystyle + \frac{\displaystyle \frac{1}{2}}{\displaystyle \frac{1}{4}\displaystyle -\frac{1}{3}}}{\displaystyle \frac{1}{2}\displaystyle - \frac{3}{\displaystyle 2-\frac{2}{7}}}</math> | ||
</div>{{#NAVCONTENT:Svar|Svar 1.2:6|Lösning |Lösning 1.2:6}} | </div>{{#NAVCONTENT:Svar|Svar 1.2:6|Lösning |Lösning 1.2:6}} | ||
Revision as of 10:53, 3 August 2008
| Teori | Övningar |
Övning 1.2:1
Write as one fraction
| a) | \displaystyle \displaystyle \frac{7}{4}+\frac{11}{7} | b) | \displaystyle \displaystyle \frac{2}{7}-\frac{1}{5} | c) | \displaystyle \displaystyle \frac{1}{6}-\frac{2}{5} |
| d) | \displaystyle \displaystyle \frac{1}{3}+\frac{1}{4}+\frac{1}{5} | e) | \displaystyle \displaystyle \frac{8}{7}+\frac{3}{4}-\frac{4}{3} |
Svar
Loading...
Lösning a
Lösning b
Lösning c
Lösning d
Lösning e
Övning 1.2:2
Determine the lowest common denominator of
| a) | \displaystyle \displaystyle \frac{1}{6}+\frac{1}{10} | b) | \displaystyle \displaystyle \frac{1}{4}-\frac{1}{8} |
| c) | \displaystyle \displaystyle \frac{1}{12}-\frac{1}{14} | d) | \displaystyle \displaystyle \frac{2}{45}+\frac{1}{75} |
Svar
Lösning a
Lösning b
Lösning c
Lösning d
Övning 1.2:3
Calcualte the following by using the lowest common denominator.
| a) | \displaystyle \displaystyle\frac{3}{20}+\frac{7}{50}-\frac{1}{10} | b) | \displaystyle \displaystyle\frac{1}{24}+\frac{1}{40}-\frac{1}{16} |
Övning 1.2:4
Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.
| a) | \displaystyle \displaystyle\frac{\displaystyle\frac{3}{5}}{\displaystyle\frac{7}{10}} | b) | \displaystyle \displaystyle\frac{\displaystyle\frac{2}{7}}{\displaystyle\frac{3}{8}} | c) | \displaystyle \displaystyle\frac{\displaystyle\frac{1}{4}-\frac{1}{5}}{\displaystyle\frac{3}{10}} |
Övning 1.2:5
Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form.
| a) | \displaystyle \displaystyle \frac{2}{\displaystyle \frac{1}{7}\displaystyle -\frac{1}{15}} | b) | \displaystyle \displaystyle\frac{\displaystyle\frac{1}{2}\displaystyle+\frac{1}{3}}{\displaystyle\frac{1}{3}\displaystyle-\frac{1}{2}} | c) | \displaystyle \displaystyle\frac{\displaystyle\frac{3}{10}\displaystyle-\frac{1}{5}}{\displaystyle\frac{7}{8}\displaystyle-\frac{3}{16}} |
Övning 1.2:6
Simplify \displaystyle \ \,\displaystyle \frac{\displaystyle \frac{2}{\displaystyle 3+\frac{1}{2}}\displaystyle + \frac{\displaystyle \frac{1}{2}}{\displaystyle \frac{1}{4}\displaystyle -\frac{1}{3}}}{\displaystyle \frac{1}{2}\displaystyle - \frac{3}{\displaystyle 2-\frac{2}{7}}}
Svar
Lösning
